77 lines
2.0 KiB
Python
77 lines
2.0 KiB
Python
# 1. 列表反转
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lst = [1, 2, 3, 4, 5]
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reversed_lst = lst[::-1]
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print(f"反转后的列表是 {reversed_lst}")
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# 2. 查找列表中的最大值和最小值
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lst = [3, 1, 7, 5, 2]
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max_value = max(lst)
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min_value = min(lst)
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print(f"最大值是 {max_value}")
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print(f"最小值是 {min_value}")
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# 3. 字典的键值交换
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d = {'a': 1, 'b': 2, 'c': 3}
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reversed_dict = {v: k for k, v in d.items()}
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print(f"反转后的字典是 {reversed_dict}")
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# 4. 集合的并集、交集、差集运算
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set1 = {1, 2, 3}
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set2 = {3, 4, 5}
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union = set1 | set2
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intersection = set1 & set2
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difference = set1 - set2
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print(f"并集是 {union}")
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print(f"交集是 {intersection}")
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print(f"差集是 {difference}")
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# 5. 元组拆包
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t = (1, 2, 3, 4)
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a, b, c, d = t
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print(f"拆包后的元素是 {a} {b} {c} {d}")
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# 6. 列表去重
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lst = [1, 2, 2, 3, 3, 4]
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unique_lst = list(set(lst))
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print(f"去重后的列表是 {unique_lst}")
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# 7. 列表中查找出现次数最多的元素
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from collections import Counter
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lst = [1, 2, 3, 1, 1, 2, 4]
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counter = Counter(lst)
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most_common_element = counter.most_common(1)[0][0]
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print(f"出现次数最多的元素是 {most_common_element}")
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# 8. 计算字典中所有值的总和
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d = {'Alice': 20, 'Bob': 25, 'Charlie': 30}
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total = sum(d.values())
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print(f"字典中所有值的总和是 {total}")
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# 9. 字典合并
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dict1 = {'a': 1, 'b': 2}
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dict2 = {'c': 3, 'd': 4}
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merged_dict = {**dict1, **dict2}
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print(f"合并后的字典是 {merged_dict}")
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# 10. 从列表中删除指定元素
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lst = [1, 2, 3, 1, 4, 1, 5]
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remove_element = 1
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new_lst = [x for x in lst if x != remove_element]
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print(f"删除后的列表是 {new_lst}")
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# 11. 列表中的嵌套字典
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lst = [{'name': 'Alice', 'age': 20}, {'name': 'Bob', 'age': 25}]
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key = 'name'
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values = [d[key] for d in lst if key in d]
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print(f"所有的 '{key}' 值是 {values}")
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# 12. 找出列表中的最大和最小元素的差值
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lst = [10, 2, 8, 6, 4]
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max_val = max(lst)
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min_val = min(lst)
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diff = max_val - min_val
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print(f"最大值和最小值之间的差是 {diff}")
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