33 lines
997 B
Python
33 lines
997 B
Python
'''
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案例：
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满足年龄在18到21,存款大于等于5000,小于等于5500的人
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开卡格式为:尊贵VIP卡老X(姓氏),
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否则开卡格式为:抠脚大汉老X(姓氏)
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把开卡的种类统计出来
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'''
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list = [
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{"name": "刘鑫炜", "age": 18, "money": 10000},
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{"name": "刘聪", "age": 19, "money": 5100},
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{"name": "刘子豪", "age": 20, "money": 4800},
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{"name": "孔祥群", "age": 21, "money": 2000},
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{"name": "宋云杰", "age": 18, "money": 20}
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]
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# s1 = set() # 创建一个空的集合
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# for item in list:
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# if 18<=item['age']<=21 and 5000<=item['money']<=5500:
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# s1.add('尊贵VIP卡老'+item['name'][0])
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# else:
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# s1.add('抠脚大汉老'+item['name'][0])
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# print(s1) # {'抠脚大汉老孔', '尊贵VIP卡老刘', '抠脚大汉老宋', '抠脚大汉老刘'}
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# 推导式实现
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print({'尊贵VIP卡老'+item['name'][0] if 18<=item['age']<=21 and 5000<=item['money']<=5500 else '抠脚大汉老'+item['name'][0] for item in list})
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