130 lines
4.7 KiB
Python
130 lines
4.7 KiB
Python
# 案例一
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# dictionary = {'a': '1234', 'B': 'FFFF', 'c': ' 23432', 'D': '124fgr', 'e': 'eeeee', 'F': 'QQQQQ'}
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# 1：获取字典中key值是小写字母的键值对
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# print(dictionary.items())
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#[('a', '1234'), ('B', 'FFFF'), ('c', ' 23432'), ('D', '124fgr'), ('e', 'eeeee'), ('F', 'QQQQQ')]
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# newdict = {key:value for key,value in dictionary.items() if key.islower()} # key:字典中的每一个键 value:每一个值
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# print(newdict) # {'a': '1234', 'c': ' 23432', 'e': 'eeeee'}
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# 2：将字典中的所有key设置为小写
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# newdict = {key.lower():value for key,value in dictionary.items()}
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# print(newdict)
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# {'a': '1234', 'b': 'FFFF', 'c': ' 23432', 'd': '124fgr', 'e': 'eeeee', 'f': 'QQQQQ'}
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# 3：将字典中所有key是小写字母的value统一赋值为'error'
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# 思路：
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# 正常输出的是key为大写字母的
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# not:取反
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# not key.islower()：不是小写字母
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# newdict = {key:value if not key.islower() else 'error' for key,value in dictionary.items()}
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# print(newdict)
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# {'a': 'error', 'B': 'FFFF', 'c': 'error', 'D': '124fgr', 'e': 'error', 'F': 'QQQQQ'}
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# 案例二
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# 将下面的字符串转换成字典
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# 思路：
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# cookie字符串有规律的，每一组值后面都有= 然后通过; 连接起来
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# cookies = "anonymid=jy0ui55o-u6f6zd; depovince=GW; _r01_=1; JSESSIONID=abcMktGLRGjLtdhBk7OVw; ick_login=a9b557b8-8138-4e9d-8601-de7b2a633f80"
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# print(cookies.split('; ')) # 利用规律将字符串拆分成列表
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# ['anonymid=jy0ui55o-u6f6zd', 'depovince=GW', '_r01_=1', 'JSESSIONID=abcMktGLRGjLtdhBk7OVw', 'ick_login=a9b557b8-8138-4e9d-8601-de7b2a633f80']
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# 将上面的拆分的列表继续变成元组，然后解构成字典的键值对
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# str = 'anonymid=jy0ui55o-u6f6zd'
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# print(str.split('=')) # ['anonymid', 'jy0ui55o-u6f6zd']
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# print((str.split('='),)) # (['anonymid', 'jy0ui55o-u6f6zd'],) 注意逗号，如果元组只有一项值，必须添加逗号
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# dict = {key:value for item in cookies.split('; ') for key,value in (item.split('='),)}
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# print(dict)
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"""
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{
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'anonymid': 'jy0ui55o-u6f6zd',
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'depovince': 'GW',
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'_r01_': '1',
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'JSESSIONID': 'abcMktGLRGjLtdhBk7OVw',
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'ick_login': 'a9b557b8-8138-4e9d-8601-de7b2a633f80'
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}
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"""
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# 案例二(换一种写法)
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# cookies = "anonymid=jy0ui55o-u6f6zd; depovince=GW; _r01_=1; JSESSIONID=abcMktGLRGjLtdhBk7OVw; ick_login=a9b557b8-8138-4e9d-8601-de7b2a633f80"
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# dict = {}
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# list = cookies.split('; ')
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# for item in list:
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# dict[item.split('=')[0]] = item.split('=')[1]
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# print(dict)
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# 推导式实现
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# print({item.split('=')[0]:item.split('=')[1] for item in cookies.split('; ')})
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# 案例三
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# 将字符串转换成字典
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# str = "k:1|k1:2|k2:3|k3:4"
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# 将字符串转换成字典需要两步
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# 第一步：将字符串拆分成列表['k:1','k1:2','k2:3','k3:4']
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# 第二步：将列表的每一项继续通过冒号拆分成两项，第一项就是键，第二项就是值
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# print({item.split(':')[0] : item.split(':')[1] for item in str.split('|')})
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# {'k': '1', 'k1': '2', 'k2': '3', 'k3': '4'}
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# print({key:value for item in str.split('|') for key,value in (item.split(':'),)})
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# 注意后面的for循环转换成元组
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# {'k': '1', 'k1': '2', 'k2': '3', 'k3': '4'}
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# 案例四
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# 生成一个包含5个随机数的字典
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# import random # 导入内置的模块
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# print(random.randint(1,100)) # 生成随机数
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# print({i : random.randint(1,100) for i in range(1,6)})
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# {1: 66, 2: 16, 3: 56, 4: 16, 5: 79}
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# 案例五
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# 将两个长度相同的列表合并成字典
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# name = ['zhangsan', 'lisi', 'wangwu', 'maliu']
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# sign = ['双鱼座', '天蝎座', '水瓶座', '巨蟹座']
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# 思路：利用元组解构字典的键值对，需要将上面的两个列表变成元组
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# print(tuple(zip(name,sign)))
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# (('zhangsan', '双鱼座'), ('lisi', '天蝎座'), ('wangwu', '水瓶座'), ('maliu', '巨蟹座'))
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# print(list(zip(name,sign)))
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# [('zhangsan', '双鱼座'), ('lisi', '天蝎座'), ('wangwu', '水瓶座'), ('maliu', '巨蟹座')]
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# print({name:value for name,value in tuple(zip(name,sign)) })
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# {'zhangsan': '双鱼座', 'lisi': '天蝎座', 'wangwu': '水瓶座', 'maliu': '巨蟹座'}
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# print({name:value for name,value in list(zip(name,sign)) })
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# {'zhangsan': '双鱼座', 'lisi': '天蝎座', 'wangwu': '水瓶座', 'maliu': '巨蟹座'}
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# 案例六
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# 将key中大小写相同的字母的value值求和
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# dict = {'a': 2, 'B': 5, 'A': 7, 'C': 10,'b':10}
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# lower() upper()
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# in
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# print({key.lower():dict.get(key.lower(),0) + dict.get(key.upper(),0) for key in dict.keys() if key.lower() in ['a','b','c']})
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# {'a': 9, 'b': 5, 'c': 10}
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# # 案例七
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# 将字典中key、value互换位置
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# 将字典转换成能够被解构的元组
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d = {1: 'a', 2: 'b', 3: 'c'}
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print({value:key for key,value in d.items()})
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